The two ends of a metal rod are maintained at temperature `100^(@)C` and `110^(@)C`. The rate of heat flow in the rod is found to be `4.0 J//s`. If the ends are maintained at temperature s `200^(@)C` and `210^(@)C`. The rate of heat flow will be

Options

A. 44.0 J/s
B. 16.8 J/s
C. 8.0 J/s
D. 4.0 J/S

Answer

D

Explanation

Temperature difference is same for both the cases and rate of heat flow `((Delta Q)/(Delta t) )` is directly proportional to the temperature difference.
` therefore if (Delta Q_1)/(Delta t) = 4 J//s`
`(Delta Q_2)/(Delta t) = 4 J//s `