A small water droplet of mass 1g carries a charge of `8xx10^(-19)`C. What electric field strength is required to suspend the droplet against gravity ?

Explanation

To find the electric field strength required to suspend a small water droplet against gravity, we can follow these steps:

### Step 1: Identify the given values
- Mass of the water droplet, \( m = 1 \, \text{g} = 1 \times 10^{-3} \, \text{kg} \)
- Charge of the droplet, \( q = 8 \times 10^{-19} \, \text{C} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)

### Step 2: Calculate the gravitational force acting on the droplet
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