Two equal and opposite charges of magnitude 10 `muC` each are fixed at a distance of 1 mm from each other to form an electric dipole . Calculate the electric field intensity (i) at a point on its axis at a distance 1 m from the centre of dipole and (ii)at a point on its perpendicular bisector at a distance 1 m from the centre of dipole.

Explanation

To solve the problem, we need to calculate the electric field intensity at two different points related to an electric dipole formed by two equal and opposite charges of magnitude \(10 \, \mu C\) each, separated by a distance of \(1 \, mm\).

### Given Data:
- Charge, \(q = 10 \, \mu C = 10 \times 10^{-6} \, C\)
- Separation between charges, \(a = 1 \, mm = 1 \times 10^{-3} \, m\)
- Distance from the center of the dipole to the point of interest, \(r = 1 \, m\)
- Coulomb's constant, \(k = 9 \times 10^9 \, N m^2/C^2\)

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