Home
Class 12
PHYSICS
A cylindrical suface is placed in unifor...

A cylindrical suface is placed in uniform electric field in such a manner that axis of cylinder is parallel to the electric field intensity . Using the Gauss's law , prove that the net charge enclosed by this cylindrical surface must be zero.

Text Solution

AI Generated Solution

To prove that the net charge enclosed by a cylindrical surface placed in a uniform electric field (with the axis of the cylinder parallel to the electric field) is zero using Gauss's law, we can follow these steps: ### Step 1: Understand the Setup We have a cylindrical surface in a uniform electric field, with the axis of the cylinder aligned parallel to the direction of the electric field. ### Step 2: Apply Gauss's Law Gauss's law states that the electric flux through a closed surface is equal to the charge enclosed divided by the permittivity of free space (ε₀): \[ ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTRIC CHARGES AND FIELDS

    MODERN PUBLICATION|Exercise Practice Problems|88 Videos
  • ELECTRIC CHARGES AND FIELDS

    MODERN PUBLICATION|Exercise Conceptual Questions|51 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|15 Videos
  • ELECTROMAGNETIC INDUCTION

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST FOR BOARD EXAMINATION|14 Videos

Similar Questions

Explore conceptually related problems

A closed cylinder is placed in uniform electric field.Find electric flux passing through cylinder.

A metal slab is placed in a uniform electric field vecE . What will be the net electric field intensity inside it?

Knowledge Check

  • A cyclinder of radius r and length l is placed in an uniform electric field in such a way that the axis of the cyclinder is parallel to the field. The flux of the field through the cyclindrical surface is

    A
    `(2rl)/(epsilon_(0))`
    B
    `(l)/(epsilon_(0))`
    C
    `(2pirl)/(epsilon_(0))`
    D
    zero
  • The electric field intensity on the surface of a charged conductor is

    A
    zero
    B
    directed normally to the surface
    C
    directed tangentially to the surface
    D
    directed along `45^(@)` to the surface
  • The electric field intensity on the surface of a charged conductor is

    A
    zero
    B
    directed normally to the surface
    C
    directed tangentially to the surface
    D
    directed along `45^(@)` to the surface
  • Similar Questions

    Explore conceptually related problems

    Consider a cylindrical surface of radius R and length l in a uniform electric field E. Compute the electric flux if the axis of the cylinder is parallel to the field direction.

    If a uniform electric field in existing inside a cube, then the net charge enclosed inside the cube is ___

    The net charge of a system is zero. Will the electric field intensity due to this system also be zero.

    Why is electric field intensity inside a charged conductor zero ?

    A cylinder of radius r and length l is placed in an uniform electric field parallel to the axis of the cylinder. The total flux for the surface of the cylinder is given by-