Home
Class 12
PHYSICS
A point charge Q is placed at the centre...

A point charge Q is placed at the centre of circular disc of radius r . Calculate the electric flux associated with circular disc.

Text Solution

AI Generated Solution

To solve the problem of calculating the electric flux associated with a circular disc when a point charge \( Q \) is placed at its center, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electric Flux**: Electric flux (\( \Phi_E \)) through a surface is defined as the product of the electric field (\( E \)) and the area (\( A \)) of the surface, integrated over the surface. Mathematically, it is given by: \[ \Phi_E = \int \vec{E} \cdot d\vec{A} ...
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CHARGES AND FIELDS

    MODERN PUBLICATION|Exercise Practice Problems|88 Videos
  • ELECTRIC CHARGES AND FIELDS

    MODERN PUBLICATION|Exercise Conceptual Questions|51 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|15 Videos
  • ELECTROMAGNETIC INDUCTION

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST FOR BOARD EXAMINATION|14 Videos

Similar Questions

Explore conceptually related problems

A point charge q is placed at a distance d form the center of circular disc of radius R . Find electric flux through the disc due to that charge

A point charge Q is placed at the centre of a circular wire of radius R having charge q . Find the force of electrostatic interaction between point charge and the wire.

a point charge q is placed at the centre of a cylinder of length L and radius R the electric flux through the curved surface of the cylinder is

A charge q is placed at the centre of a cylinder of radius R and length 2R. Then electric flux through the curved surface of the cylinder is

A charge 'Q' is placed at the centre of a hemispherical surface of radius 'R'. The flux of electric field due to charge 'Q' through the surface of hemisphere is

A position charge Q is placed at a distance of 4R above the centre of a disc of radius R. The magnitude of flux through the disc is phi . Now a hemispherical shell of radius R is placed over the disc such that it forms a closed surface. The flux through the curved surface (taking direction of area vector along outward normal as positive), is -

The angular velocity of circular disc of radius 2cm is 20 rad s^(-1) . Calculate the linear velocity of the disc.

A point charge 'q' is placed at the centre of left circular end of a cylinder of length l=4cm and radius R=3 cm shown. Then the electric flux through the curved surface of the cylinder is

MODERN PUBLICATION-ELECTRIC CHARGES AND FIELDS -Chapter Practice Test
  1. A point charge Q is placed at the centre of circular disc of radius r ...

    Text Solution

    |

  2. Why electrostatic field is normal to the surface at every point of a c...

    Text Solution

    |

  3. Define electric dipole moment. Write its SI unit ?

    Text Solution

    |

  4. when an electric dipole is suspended in a uniform electric field, then...

    Text Solution

    |

  5. Two charged particles are placed at a distance r from each other. The ...

    Text Solution

    |

  6. An electric dipole having dipole moment 2 xx 10^(-6) C-m is enclosed b...

    Text Solution

    |

  7. Two infinitely long parallel wires having linear charge density 3 xx 1...

    Text Solution

    |

  8. In a region of space uniform electric field vecE=2xx10^(3) hati NC^(-1...

    Text Solution

    |

  9. Two charges of magnitude -2Q and +Q are located at points (a,0) and (...

    Text Solution

    |

  10. What are electric field lines? Why do two field lines never intersect ...

    Text Solution

    |

  11. Equal charges q are placed at the four corners A,B,C,Dof a square of l...

    Text Solution

    |

  12. Using Gauss's law obtain the expression for the electric field due to ...

    Text Solution

    |

  13. Two small identical electrical dipoles AB and CD, each of dipole momen...

    Text Solution

    |

  14. A conducting ring of radius 40 cm has a charge of 5 xx 10^(-9) C unifo...

    Text Solution

    |

  15. A thin straight infinitely long conducting wire having charge density ...

    Text Solution

    |

  16. In Fig, electric field is directed along +X direction and is given by...

    Text Solution

    |