Three identical charges of 2mC are kept on the vertices of an equilateral triangle of side 10 cm. A third charge of 1 mC is kept on the centroid of the triangle Calculate the force acting on the charge 1mC.

Explanation

To solve the problem, we will calculate the net force acting on the charge of 1 mC placed at the centroid of the equilateral triangle formed by three identical charges of 2 mC at its vertices.

### Step-by-step Solution:

1. **Identify the Charges and Their Positions:**
- Let the three identical charges at the vertices of the equilateral triangle be \( Q = 2 \, \text{mC} = 2 \times 10^{-3} \, \text{C} \).
- The charge at the centroid is \( q = 1 \, \text{mC} = 1 \times 10^{-3} \, \text{C} \).
- The side length of the triangle \( a = 10 \, \text{cm} = 0.1 \, \text{m} \).
...