Two identical charge of magnitude +2 `muC`are kept on two diagonally opposite vertices of a square of side a. Both the charges are joined using an insulated massless chord. What will be the tension in the chord? Neglect the gravitational forces involved.

Explanation

To find the tension in the chord connecting two identical charges of magnitude +2 µC placed at diagonally opposite vertices of a square of side 'a', we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Charges and Their Positions**:
- Let the two charges be \( q_1 = q_2 = +2 \, \mu C = 2 \times 10^{-6} \, C \).
- Place the charges at diagonally opposite corners of a square with side length \( a \).

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