Two charges `+0.4 muC` and`-0.2 muC` are placed on adjacent vertices of a square of side 10 cm. Another charge of `1.2muC` is placed at the centre af the square Calculate the force and its direction in the charge kept in the centre .

Explanation

To solve the problem step by step, we will calculate the forces acting on the charge at the center of the square due to the other two charges and then find the resultant force and its direction.

### Step 1: Identify the charges and their positions
- Charge \( q_1 = +0.4 \, \mu C = 4 \times 10^{-6} \, C \) is at one vertex of the square.
- Charge \( q_2 = -0.2 \, \mu C = -2 \times 10^{-6} \, C \) is at the adjacent vertex of the square.
- Charge \( q_3 = +1.2 \, \mu C = 1.2 \times 10^{-6} \, C \) is at the center of the square.

### Step 2: Calculate the distance from the center to the corners
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