Two point charges of magnitude 4 `mu`C and-4`mu`C are kept at points (-2 cm, 0) and (2 cm, 0) respectively. Calculate the magnitude of electric field intensity at points (0, 2 cm).

Explanation

To find the magnitude of the electric field intensity at the point (0, 2 cm) due to the two point charges of +4 µC and -4 µC located at (-2 cm, 0) and (2 cm, 0) respectively, we can follow these steps:

### Step 1: Identify the positions of the charges and the point of interest
- Charge \( Q_1 = +4 \, \mu C \) is located at \( (-2 \, \text{cm}, 0) \).
- Charge \( Q_2 = -4 \, \mu C \) is located at \( (2 \, \text{cm}, 0) \).
- The point where we need to calculate the electric field is \( P(0, 2 \, \text{cm}) \).

### Step 2: Calculate the distances from each charge to the point P
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