An electric dipole consists of two charges of `pm0.5 muC`, kept at distance of 1.0 cm. Calculate the potential energy required to place the dipole such that it makes an angle of `30^@` with the external electric field of `0.8 xx 10^4` N/C.

Explanation

To solve the problem of calculating the potential energy required to place an electric dipole in an external electric field, we can follow these steps:

### Step 1: Understand the given values
- Charge of the dipole: \( q = 0.5 \, \mu C = 0.5 \times 10^{-6} \, C \)
- Distance between the charges: \( d = 1.0 \, cm = 1.0 \times 10^{-2} \, m \)
- External electric field: \( E = 0.8 \times 10^{4} \, N/C \)
- Angle with the electric field: \( \theta = 30^{\circ} \)

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