Calculate the magnitude of electric fiel...

Calculate the magnitude of electric field at the centre of a regular hexagon of side 2.5 cm, if each charge placed at its vertex has the same magnitude of +0.01 `mu`C.

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To solve the problem of calculating the magnitude of the electric field at the center of a regular hexagon with charges at its vertices, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Configuration**: - We have a regular hexagon with each side measuring 2.5 cm. - There are six identical charges of +0.01 µC placed at each vertex of the hexagon. ...

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Each side of a regular hexagon is 9.6 cm. Find its perimeter.

57.6 sq. cm

1.6 sq. cm

1.6 cm

57.6 cm

A positive charge kept at one of the vertices of a regular hexagon produces electric intensity E at the centre of the hexagon. If the charge is moved to an adjacent vertex, the magnitude of change in the electric intensity will be

zero

`sqrt(3)E`

`E`

`E//sqrt(3)`

Five identical charge +q are placed at five corner of a regular hexagon of side a. Find the magnitude of electric field at centre.

`(1)/( 4pi epsilon_(0))(q)/(a^(2))`

`(q)/( 2pi epsilon_(0)a^(2))`

`( 5q)/( 4 pi epsilon_(0)a^(2))`

`(5q)/( 2pi epsilon_(0)a^(2))`