Two point charges +4 `mu`C and -4 `mu`C are place(at vertices P and Q respectively of a right angled triangle. Calculate the magnitude and direction of electric field at a point R, if `anglePQR = 90^@`, PQ =0.03 cm and QR = 0.04 cm.

Explanation

To solve the problem of finding the electric field at point R due to the charges at points P and Q, we will follow these steps:

### Step 1: Understand the configuration
We have two point charges:
- Charge at P: \( +4 \, \mu C = +4 \times 10^{-6} \, C \)
- Charge at Q: \( -4 \, \mu C = -4 \times 10^{-6} \, C \)

The distances given are:
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