Refer to the arrangement of charges in Fig and a Gaussian surface of radius `R` with `Q` at the centre. Then

Options

A. total flux through the surface of the sphere is `-Q/epsilon_0`
B. field on the surface of the sphere is `-Q/(4piepsilon_0R^2)`
C. flux through the surface of sphere due to 5Q is zero
D. field on the surface of sphere due to -2Q is same everywhere.

Answer

A, C

Explanation

Net enclosed charge within the Gaussian surface is-Q, hence electric flux linked with it must, be `-Q/epsilon_0` . On the other hand charge 5Q is outside the Gaussian surface, hence the electric flux will be zero.