A metal spherical shell has an inner radius `R_(1)` and outer radius `R_(2)`. A charge Q is placed at the center of the spherical cavity. What will be surface charge density on (i) the inner surface, and (ii) the outer surface ?

Explanation

Due to induction, -Q charge will be distributed uniformly on the inner surface of the shell. And +Q charge will be distributed uniformly on the outer surface of the shell `R_2`.

Hence, the charge densities on the inner and outer surfaces are `(-Q)/(4piR_1^2)` and `(+Q)/(4piR_2^2)` respectively.