Two points having charges `q_(1) and q_(2)` are placed at the coordinates (a, 0, 0) and (0, b, 0) respectively. Find out the electric field intensity of a third point charge placed at (0, 0, c) due to those two charges.

Explanation

Electric field at given point having coordinates (0,0,c) due to `q_1` is given by, `1/(4piepsilon_0)q_1/(a^2+c^2)^(3//2) (-ahati+chatj)`
Electric field at given point having coordinates (0,0,c) due to `q_2` is given by ,`1/(4piepsilon_0)q_2/(b^2+c^2)^(3//2) (-bhatj+chatk)`
Net electric field at the given point is given by :
`E=1/(4piepsilon_0)q_1/(a^2+c^2)^(3//2) (-ahati+chatj) + 1/(4piepsilon_0)q_2/(b^2+c^2)^(3//2) (-bhatj+chatk)`
`vecE=1/(4piepsilon_0)[q_1((-ahati+chatj))/(a^2+c^2)^(3//2)+q_2((-bhatj+chatk))/(b^2+c^2)^(3//2)]`