A positive charge `q` is placed in front of a conducting solid cube at a distance `d` from its centre. Find the elcetric field at the centre of the cube due to the charges appearing on its surgace.

Options

A. `q/(4piepsilon_0d^2)`, directed away from point charge
B. `q/(4piepsilon_0d^2)`, directed towards the point charge
C. zero
D. None

Answer

B

Explanation

As soon as the condition of electrostatics is attained the net electric field intensity inside the conductor becomes zero. Hence, the electric field intensity due to induced charges at the centre of cube will be equal and opposite to the field created by the point charge.