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An electron of mass `m_e` starts from rest, moves a certain distance in uniform field and takes time `t_1`. A proton of mass `m_p` also starts from rest in the same field and covers the same distande in time `t_2` ,then `t_1//t_2` is equal to

A

`sqrt(m_e/m_p)`

B

`sqrt(m_p/m_e)`

C

1

D

1836

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of both the electron and the proton in a uniform electric field. Here’s a step-by-step solution: ### Step 1: Understand the Forces Acting on the Particles Both the electron and the proton experience a force due to the electric field \( E \). The force \( F \) acting on a charged particle in an electric field is given by: \[ F = qE \] where \( q \) is the charge of the particle. ### Step 2: Determine the Acceleration of Each Particle The acceleration \( a \) of each particle can be found using Newton's second law: \[ F = ma \] Thus, we can express the acceleration as: \[ a = \frac{F}{m} = \frac{qE}{m} \] For the electron (charge \( -e \), mass \( m_e \)): \[ a_e = \frac{eE}{m_e} \] For the proton (charge \( +e \), mass \( m_p \)): \[ a_p = \frac{eE}{m_p} \] ### Step 3: Use Kinematic Equations Since both particles start from rest and travel the same distance \( s \), we can use the kinematic equation: \[ s = ut + \frac{1}{2} a t^2 \] Given that the initial velocity \( u = 0 \), this simplifies to: \[ s = \frac{1}{2} a t^2 \] For the electron: \[ s = \frac{1}{2} a_e t_1^2 = \frac{1}{2} \left(\frac{eE}{m_e}\right) t_1^2 \] For the proton: \[ s = \frac{1}{2} a_p t_2^2 = \frac{1}{2} \left(\frac{eE}{m_p}\right) t_2^2 \] ### Step 4: Set the Distances Equal Since both particles travel the same distance \( s \), we can set the two equations equal to each other: \[ \frac{1}{2} \left(\frac{eE}{m_e}\right) t_1^2 = \frac{1}{2} \left(\frac{eE}{m_p}\right) t_2^2 \] The \( \frac{1}{2} \) and \( eE \) terms cancel out: \[ \frac{t_1^2}{m_e} = \frac{t_2^2}{m_p} \] ### Step 5: Solve for the Ratio of Times Rearranging gives: \[ \frac{t_1^2}{t_2^2} = \frac{m_e}{m_p} \] Taking the square root of both sides: \[ \frac{t_1}{t_2} = \sqrt{\frac{m_e}{m_p}} \] ### Final Answer Thus, the ratio of the times \( t_1 \) and \( t_2 \) is: \[ \frac{t_1}{t_2} = \sqrt{\frac{m_e}{m_p}} \]

To solve the problem, we need to analyze the motion of both the electron and the proton in a uniform electric field. Here’s a step-by-step solution: ### Step 1: Understand the Forces Acting on the Particles Both the electron and the proton experience a force due to the electric field \( E \). The force \( F \) acting on a charged particle in an electric field is given by: \[ F = qE \] where \( q \) is the charge of the particle. ...
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MODERN PUBLICATION-ELECTRIC CHARGES AND FIELDS -COMPETITION FILE ( Objective Question (A.MCQ) )
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  2. A solid sphere of radius R has a charge Q distributed in its volume wi...

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  6. A point charge is placed at the midpoint of an edge of cube. How much ...

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  9. A positively charged rod lies along X-axis in such a manner that one e...

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  10. Conisder a neutral conducting sphere. A poistive point charge is place...

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  11. A thin metallic ring of radius R and area of cross section A carries a...

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  12. What is the change in radius of ring ?

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  13. There is one long non-conducting solid cylinder of radius R. The volum...

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  14. Two uniform sheets of charge with surface charge densities +sigma and ...

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  17. Two electric dipoles are placed in such a manner that their electric d...

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