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The time period of revolution of a charg...

The time period of revolution of a charge `q_1` and of mass m moving in a circular path of radius r due to Coulomb force of attraction due to another charge `q_2` at its centre is

A

`sqrt((16piepsilon_0mr^3)/(q_1q_2))`

B

`sqrt((8pi^2epsilon_0mr^3)/(q_1q_2))`

C

`sqrt((epsilon_0mr^3)/(16q_1q_2))`

D

`sqrt((16pi^3epsilon_0mr^3)/(q_1q_2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the time period of revolution of a charge \( q_1 \) of mass \( m \) moving in a circular path of radius \( r \) due to the Coulomb force of attraction from another charge \( q_2 \) at its center, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Charge**: The charge \( q_1 \) is moving in a circular path due to the electrostatic force exerted by the charge \( q_2 \). This force can be expressed using Coulomb's law: \[ F = \frac{1}{4 \pi \epsilon_0} \frac{q_1 q_2}{r^2} \] 2. **Centripetal Force Requirement**: For \( q_1 \) to move in a circular path, the centripetal force required for circular motion must equal the electrostatic force. The centripetal force \( F_c \) is given by: \[ F_c = \frac{m v^2}{r} \] where \( v \) is the velocity of the charge \( q_1 \). 3. **Set the Forces Equal**: Setting the electrostatic force equal to the centripetal force gives us: \[ \frac{1}{4 \pi \epsilon_0} \frac{q_1 q_2}{r^2} = \frac{m v^2}{r} \] 4. **Solve for Velocity \( v \)**: Rearranging the equation to solve for \( v^2 \): \[ v^2 = \frac{q_1 q_2}{4 \pi \epsilon_0 m r} \] Taking the square root gives: \[ v = \sqrt{\frac{q_1 q_2}{4 \pi \epsilon_0 m r}} \] 5. **Calculate the Time Period \( T \)**: The time period \( T \) of one complete revolution is given by the distance traveled in one revolution divided by the velocity: \[ T = \frac{2 \pi r}{v} \] Substituting the expression for \( v \): \[ T = \frac{2 \pi r}{\sqrt{\frac{q_1 q_2}{4 \pi \epsilon_0 m r}}} \] 6. **Simplify the Expression**: To simplify, we can multiply the numerator and denominator by \( \sqrt{4 \pi \epsilon_0 m r} \): \[ T = \frac{2 \pi r \sqrt{4 \pi \epsilon_0 m r}}{\sqrt{q_1 q_2}} \] This simplifies to: \[ T = 2 \pi \sqrt{\frac{4 \pi \epsilon_0 m r^3}{q_1 q_2}} \] 7. **Final Result**: Thus, the final expression for the time period \( T \) is: \[ T = 2 \pi \sqrt{\frac{4 \pi \epsilon_0 m r^3}{q_1 q_2}} \]
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