The value of end correction for the pipe open at both the ends is a
(If the d is the inner diameter of the tube and r is the radius of the tube .)

Options

A. n=1
B. n=2
C. n=-1
D. n=-2

Answer

C

Explanation

Electric field intensity at a distance x from the centre of pipe can be written using formula for line charge, Note that we are considering x > R.
`E=lambda/(2piepsilon_0x)`
On substituting the value of À in the above equation, we get the final expression for the electric field as follows.
`E=(Q/"2r")/(2piepsilon_0x) rArr E =1/(4piepsilon_0x)(Q/r)=y/(4piepsilon_0x)`
`E prop x^n`
`rArr` n=-1