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There is one short electric dipole place...

There is one short electric dipole placed on a plane. A straight line is drawn on this plane passing through the centre of electric dipole making an angle `theta` with the axis of dipole. A point P is selected on this line at a distance ten times the length of electric dipole from centre of electric dipole. Electric field intensity at the point P makes an angle `alpha` with the axis of electric dipole . What will be the magnitude of `(tan theta)/(tan alpha)` ?

Text Solution

Verified by Experts

The correct Answer is:
2
We should know that `tan alpha =1/2 tantheta`
`rArr (tan theta)/(tan alpha)=2`
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Knowledge Check

  • At a point on the axis of an electric dipole

    A
    the electric field E is zero
    B
    the electric potential V is zero
    C
    both E and V are zero
    D
    neither E nor V is zero

  • Total electric force on an electric dipole placed in an electric field of a point charge is :

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    B
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    C
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    D
    zero when dipole axis is along any electric line of force.

  • The work in rotating electric dipole of dipole moment p in an electric field E through an angle theta from the direction of electric field, is:

    A
    `pE(1- cos theta)`
    B
    `pE`
    C
    zero
    D
    `-pE cos theta`

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