Two point objects of masses 10 g each carry charges of opposite nature with the same magnitude of 50 `muC` are held at rest at a separation of 2 m. Now the point objects are released from the state of rest. Calculate the speed acquired by both the objects when separation between them reduces to half of the initial value.

Explanation

To solve the problem, we need to calculate the speed acquired by two point objects of mass 10 g each, carrying charges of opposite nature (50 µC each), when the separation between them reduces from 2 m to 1 m.

### Step-by-Step Solution

1. **Identify Given Data:**
- Mass of each object, \( m = 10 \, \text{g} = 10 \times 10^{-3} \, \text{kg} = 0.01 \, \text{kg} \)
- Charge of each object, \( q_1 = +50 \, \mu\text{C} = 50 \times 10^{-6} \, \text{C} \) and \( q_2 = -50 \, \mu\text{C} = -50 \times 10^{-6} \, \text{C} \)
- Initial separation, \( r_1 = 2 \, \text{m} \)
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