A uniform electric field of 2,000 N/C exists in space. Consider a right angled triangle `DeltaABC` such that `angleABC` is a right angle. Edge AB of the triangle is kept parallel to electric field. Edge AB is 3cm long and edge BC is 4cm long. Calculate potential difference `V_(A)-V_(C )`. Is the answer affected by the orientation of triangle inside field keeping edge AB parallel to the field?

Explanation

To solve the problem, we need to calculate the potential difference \( V_A - V_C \) in a uniform electric field of \( 2000 \, \text{N/C} \). The triangle \( \Delta ABC \) has sides \( AB \) and \( BC \) with lengths \( 3 \, \text{cm} \) and \( 4 \, \text{cm} \), respectively, and \( AB \) is parallel to the electric field.

### Step-by-Step Solution

1. **Identify the Coordinates of Points A, B, and C**:
- Let point \( B \) be at the origin: \( B(0, 0) \).
- Since \( AB \) is parallel to the electric field and has a length of \( 3 \, \text{cm} \), point \( A \) will be at \( A(3, 0) \).
- Point \( C \) is \( 4 \, \text{cm} \) above point \( B \) (along the y-axis), so \( C(0, 4) \).
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