Electric field intensity in a region of space is given by `vecE=10x^(2)hati N//C`. What will be potential difference between point A(2, 5) and B(-1, 10)?

Explanation

To find the potential difference between points A(2, 5) and B(-1, 10) in an electric field given by \(\vec{E} = 10x^2 \hat{i}\) N/C, we will follow these steps:

### Step 1: Understand the relationship between electric field and potential difference
The potential difference \(V\) between two points A and B in an electric field is given by the negative integral of the electric field along the path from A to B:
\[ V_{AB} = -\int_A^B \vec{E} \cdot d\vec{l} \]
where \(d\vec{l}\) is the differential displacement vector along the path.
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