Two capacitors when connected in parallel are equivalent to `6muF` and when the same are connected in series then the equivalent becomes 1.5 `muF`. Calculate the individual capacitances.

Explanation

To solve the problem of finding the individual capacitances of two capacitors connected in parallel and series, we can follow these steps:

### Step 1: Understand the given information
We know that:
- When connected in parallel, the equivalent capacitance \( C_{eq} = C_1 + C_2 = 6 \, \mu F \).
- When connected in series, the equivalent capacitance \( \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} = 1.5 \, \mu F \).

### Step 2: Set up the equations
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