A capacitor of capacitance 5 `muF` is charged to a potential difference of 10 volts and another capacitor of capacitance 9 `muF` is charged to a potential difference of 8 volts. Now these two capacitors are connected in such a manner that the positive plate of one is connected to the positive plate of other. Calculate the common potential difference across the two capacitors.

Explanation

To solve the problem, we need to find the common potential difference across two capacitors when they are connected in parallel, with their positive plates connected together.

### Step-by-Step Solution:

1. **Identify the given values**:
- Capacitance of the first capacitor, \( C_1 = 5 \, \mu F \)
- Voltage across the first capacitor, \( V_1 = 10 \, V \)
- Capacitance of the second capacitor, \( C_2 = 9 \, \mu F \)
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