Calculate the work done in moving a `1muC` charge from A (5cm, 1cm) to B (1cm, 5cm) in a region of electric field of magnitude `10^(3)NC^(-1)` and directed along the line `x=y-5`.

Explanation

To calculate the work done in moving a `1 µC` charge from point A (5 cm, 1 cm) to point B (1 cm, 5 cm) in an electric field of magnitude `10^3 N/C` directed along the line `x = y - 5`, we can follow these steps:

### Step 1: Identify the Electric Field Direction
The electric field is given to be directed along the line `x = y - 5`. This can be rewritten as:
\[ y = x + 5 \]
This line has a slope of 1, indicating that the electric field vector can be expressed in terms of its components.

### Step 2: Determine the Electric Field Vector
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