Two identical charges of magnitude 0.4 mC are placed on diagonally opposite vertices of a square of side 10 cm. Calculate the amount of work done in slowly moving one of the charges from diagonally opposite vertex to adjacent vertex.

Explanation

To solve the problem of calculating the work done in moving one charge from a diagonally opposite vertex to an adjacent vertex in a square, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Charges and Positions**:
- We have two identical charges, \( Q = 0.4 \, \text{mC} = 0.4 \times 10^{-3} \, \text{C} \).
- They are placed at diagonally opposite vertices of a square with side length \( a = 10 \, \text{cm} = 0.1 \, \text{m} \).

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