Permanent dipole moment of a water molecule is 1.85 D. Calculate the electric potential at point P, `0.5xx10^(-7)` m away from the centre of the dipole on its axis.
Given: 1D (debye)`=3.33xx10^(-30)Cm.`

Explanation

To find the electric potential \( V \) at point \( P \), which is \( 0.5 \times 10^{-7} \) m away from the center of a dipole on its axis, we can use the formula for the electric potential due to a dipole:

\[ V = \frac{k \cdot p \cdot \cos(\theta)}{r^2} \]

Where:
- \( V \) is the electric potential,
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