Positive charge Q is uniformly distributed across a thin rod of length L. The rod is then bent in the form of a semicircle. What will be the electric potential at the centre of curvature of semicircle formed?

Explanation

To find the electric potential at the center of curvature of a semicircle formed by a thin rod of length \( L \) with a uniformly distributed positive charge \( Q \), we can follow these steps:

### Step 1: Determine the Radius of the Semicircle
The length of the rod \( L \) when bent into a semicircle corresponds to the semicircular arc length. The length of a semicircle is given by:

\[ L = \pi R \]
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