A parallel plate capacitor, with plate separation d and plate area A, has a capacitance of `5muF`. Calculate the new capacitance if the plate separation is reduced to 0.75d and the capacitor is completely filled with dielectric of dielectric constant 8.

Explanation

To solve the problem step by step, we will start with the formula for the capacitance of a parallel plate capacitor and apply the changes given in the question.

### Step 1: Understand the initial capacitance
The capacitance \( C \) of a parallel plate capacitor is given by the formula:
\[ C = \frac{K \cdot A \cdot \epsilon_0}{d} \]
where:
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