Home
Class 12
PHYSICS
A parallel plate capacitor with plate ar...

A parallel plate capacitor with plate area `8xx10^(-3)m^(2)`, and plate separation 0.1 cm is connected to a battery of 100 V. Calculate the dielectric constant of the medium filled completely between both the plates if it can store a charge equal to `1.5xx10^(-7)C`.

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the dielectric constant (k) of a parallel plate capacitor given the following parameters: - Plate area (A) = \(8 \times 10^{-3} \, m^2\) - Plate separation (d) = \(0.1 \, cm = 0.1 \times 10^{-2} \, m\) - Voltage (V) = \(100 \, V\) - Charge stored (Q) = \(1.5 \times 10^{-7} \, C\) ### Step-by-Step Solution: ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS 5|18 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    MODERN PUBLICATION|Exercise Conceptual Questions|37 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS 3|3 Videos
  • ELECTROMAGNETIC WAVES

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos
  • MAGNETISM AND MATTER

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST FOR BOARD EXAMINATION|16 Videos

Similar Questions

Explore conceptually related problems

A parallel-plate capacitor with plate are 20cm^(2) and plate separation 1.0mm is connected to a battery .The resistance of the circuit is 10k(Omega) .Find the time constant of the circuit.

A parallel-plate capacitor having plate are 100 cm ^2 and separation 1.0 mm holds a charge of 0.12 muC when connected to a 120 V battery. Find the dielectric constant of the material filling the gap.

A parallel plate capacitor of plate area (1xx3) m^(2) and plate separation 5.0 mm is charged to 10 kV in air. Find charge density and field displacement.

A pallel -plate capacitor whith the plate area 100cm^2 and the separation between the plate 1.0cm is connected across a battery of emf 24 volts .Find the force of attraction between the plates.

A parallel plate capacitor of plate are A and plate separation d is charged by a battery of voltage V. The battery is then disconnected. The work needed to pull the plates to a separation 2d is

A paller- plate capacitor has plate area 100cm^2 and plate separation 1.0cm.A glass plate (dielectric constant 4.0)are inserted one over the other the fill the space between the plate of the capacitor.Find the new capacitance.

A parallel-plate capacitor of plate area A and plate separation d is charged by a ideal battery of e.m.f. V and then the battery is disconnected. A slab of dielectric constant 2k is then inserted between the plates of the capacitor so as to fill the whole space between the plates. Find the change in potential energy of the system in the process of inserting the slab.

A parallel plate capacitor of plate area A and plates separation distance d is charged by applying a potential V_(0) between the plates. The dielectric constant of the medium between the plates is K. What is the uniform electric field E between the plates of the capacitor ?

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

A parallel plate capacitor is constructed with plates of area 0.0280 m^(2) and separation 0.550 mm . Find the magnitude of the charge on each plate of this capacitor when the potential between the plates is 20.1 V