A uniform electric field `vecE` exists in a region parallel to Y-axis. How much work will be done on a charge q in displacing it in this field, parallel to x-z plane?

Explanation

To solve the problem of how much work will be done on a charge \( q \) when it is displaced in a uniform electric field \( \vec{E} \) that is parallel to the y-axis, we can follow these steps:

### Step 1: Understand the Direction of the Electric Field
The electric field \( \vec{E} \) is given to be parallel to the y-axis. This means that the electric field vector can be represented as:
\[ \vec{E} = E \hat{j} \]
where \( E \) is the magnitude of the electric field and \( \hat{j} \) is the unit vector in the y-direction.
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