A capacitor of capacity C charged to potential "V" and " then connected to an identical uncharged capacitor then loss of energy is

Explanation

A total charge of CV will be distributed between the two. Hence, common potential attained by both will be V/2. Heat loss:
`H=[(1)/(2)CV^(2)+0]-[(1)/(2)C((V)/(2))^(2) +(1)/(2)C((V)/(2))^(2)]=(CV^(2))/(4)`