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The force between the plates of a parral...

The force between the plates of a parrallel plate air capacitor , if charge on capacitor is Q and area of each palte is A , will be

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The force on one plate of the capacitor is equal to charge of that plate multiplied with electric field intensity due to the other plate. Electric field intensity due to one plate is half of the net field in-between the plates. Hence,
`F=Q xx (Q)/(2epsilon_(0)A) rArr F=(Q^(2))/(2epsilon_(0)A)`
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