Home
Class 12
PHYSICS
Explain what would happen if in the capa...

Explain what would happen if in the capacitor given in Exercise 8,a 3mm thick mica sheet (of dielectric constant =6) were inserted between the plates.
(a) While the voltage supply remained connected.
(b) after the supply was disconnected.

Text Solution

Verified by Experts

(a) While the voltage supply remains connected and a dielectric slab is inserted between the plates a capacitor, the potential difference across the plates of the given capacitor remains same, i.e equal to supply voltage (V = 100V). However, capacitance and charge on the capacitor increases by K times.
`C.=KC=6xx18xx10^(-12)=108pF`
`Q.=C.V=KCV`
`=6xx18xx10^(-12)xx100=1.08xx10^(8)C`
(b) When the dielectric slab is inserted between the plates after the voltage supply is disconnected the charge on capacitor remains same and the potential difference across the plates and capacitance of the given capacitor changes as:
`V.=(V)/(K)=(100)/(6)=16.6V`
`C.=KC=6xx18xx10^(-12)=108pF`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    MODERN PUBLICATION|Exercise NCERT FILE Solved (Additional Exercises)|23 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    MODERN PUBLICATION|Exercise NCERT FILE Solved (Additional Exercises) (Answer carefully)|7 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    MODERN PUBLICATION|Exercise Tough & Tricky PROBLEMS|10 Videos

  • ELECTROMAGNETIC WAVES

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos

  • MAGNETISM AND MATTER

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST FOR BOARD EXAMINATION|16 Videos

Similar Questions

Explore conceptually related problems

Explain what would happen if in the capacitor in Q. 8, a3 mm thick mica sheet of (dielectric constant = 6) were inserted between the plates (a) while the voltage supply remained connected (b) after the supply was disconnected.

A parallel plate capacitor with air between its plates having palte area of 6xx10^(-3)m^(2) and separation between them 3 mm is connected to a 100 V supply. Calculate charge on each plate of the capacitor. Explain what would happen when a 3 mm thick mica sheet (dielectric constant=6) is inserted between the plates, (i) while the voltage supply remains conected, (ii) after the supply is disconnected.

The plates of a parallel plate capacitor with no dielectirc are connected to a volatage source. Now a dielectric of dielectric constant K is inserted to fill the whose space between the plates with voltage source remainign connected to the capacitor-

A parallel plate capacitor is charged by a battery. After some time the battery is disconnected and a dielectric slab of dielectric constant K is inserted between the plates. How would (i) the capacitance, (ii) the electric field between the plates and (iii) the energy stored in the capacitor, be affected ? Justify your answer.

Two identical capacitors A and B shown in the given circuit are joined in series with a battery. If a dielectric slab of dielectric constant K is slipped between the plates of capacitor B and battery remains connected, then the energy of capacitor A will-

A parallel plate of capacitance C_(0) is connected to a power supply V_(0) . A dielectric slab of dielectric constant K=5 is now inserted into the gap between the plates. (a) find the extra charge flown through the power supply and work done by the supply. (b) find change in energy stored in capacitor and heat produced in connecting wires.

Shown a parallel plate capacitor with plates of width b and length l . The separation between the platesis d. The plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. (a) Calculate the energy of the system when a length x of the slab is introduced into the capacitor. (b) what force should be applied on teh slab to ensure that is goes slowly into the capacitor? Neglect any effect of friction or gravity.