Two identical capacitors of plate dimensions: `l xx b` and plate separation d have dielectric slabs filled in between the space of the plates as shown in the figures. if capacitance of both capacitor is same, Obtain the relation between the dielectric constant `K, K_(1) and K_(2)`.

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

Two identical parallel plate (air) capacitors c_(1) and c_(2) have capacitances C each. The space between their plates is now filled with dielectrics as shown. If two capacitors still have equal capacitance, obtain the relation betweenn dielectric constants k,k_(1) and k_(2) .

Two dielectric slabs of constant K1 and K2 have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor

A parallel plate capacitor with each plate of dimension 10cm xx 15cm and a plate separation of 0.2 cm is filled with two slabs of dielectric media as shown in the figure. Calculate the capacitance of the capacitor if K_(1)=6 and K_(2)=9 .

Two dielctric slabs of constant K_(1) and K_(2) have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor ?

Three identical parallel plate (air) capacitors C_(1), C_(2), C_(3) have capacitances C each. The space between their plates is now filled with dielectrics as shown. If all the three capacitors still have equal capacitances, obtain the relation between the dielectric constants K, K_(1), K_(2), K_(3) and K_(4) .

calculate the effective capacitance of the connection if a dielectric material of dielectric constant K is filled in between the plates as shown in the adjoining figure (n).