In the given figure the values of five capacitors are `C_(1)=C_(2)=C_(3)=C_(4)=2muF and C_(5)=5muF`. Find the equivalent capacitance between points P and Q.

Explanation

The given circuit forms a wheat store bridge arrangement and can be redrawn as:
It is a balanced Wheat stone.s bridge, hence capacitor `C_(5)` can be removed.

`C_(1) and C_(3)` are connected in series, thus
`C.=(C_(1)C_(3))/(C_(1)+C_(3))=(2xx2)/(2+2)=1muF`
Similarly, `C_(2) and C_(5)` are connected in series, thus
`C..=(C_(5)C_(2))/(C_(5)+C_(2))=(2xx2)/(2+2)=1muF`
C. and C.. are connected in parallel, thus effective capacitance is `C.+C..=1+2=2muF`.