Two identical capacitors of 10 pF each are connected is turn (i) in series and (ii) in parallel across a 20 V battery. Calculate the potential difference across each capacitor in the first case and charge acquired by each capacitor in the second case.

Explanation

To solve the problem, we need to analyze the two configurations of the capacitors: first in series and then in parallel.

### Step 1: Capacitors in Series
When capacitors are connected in series, the total capacitance (C_total) can be calculated using the formula:

\[ \frac{1}{C_{\text{total}}} = \frac{1}{C_1} + \frac{1}{C_2} \]
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