When a battery of emf `E` volts is connected across a capacitor of capacitance `C`, then after some time the potential difference between the plates of the capacitor becomes equal to the battery voltage. The ratio of the work done by the battery and the energy stored in the capacitor when it is fully charged is

Options

A. `0.5CV^(2)`
B. `CV^(2)`
C. `2CV^(2)`
D. None of these

Answer

b

Explanation

The battery needs to supply 2CV charge to reverse the polarity. Energy stored remains same hence work done by the battery
`(W_(b)=(2CV)V=2CV^(2))` is lost as heat in recharging.