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The work done to move a charge along an ...

The work done to move a charge along an equipotential from `A` to `B`

A

cannot be defined as `-int_(A)^(B)vecE. d vecl`

B

must be defined as `-int_(A)^(B) vecE. d vecl`

C

is zero.

D

can have a non-zero value.

Text Solution

Verified by Experts

The correct Answer is:
C

The work done to move a charge in an external electric field `vecE` from point A to B is given by:
`W=q(V_(B)-V_(A))`
`(V_(B)-V_(A))`, is the potential difference between the points A and B.
For equipotential surface `V_(A)=V_(B)`, hence W = 0.
`-int_(A)^(B) vecE. d vecl` given in option (b) is equal to potential difference between two points. Hence it cannot be used as work done because it is equal to work done in moving a unit positive charge from a point to the other, although it will also be equal to zero when integrated on an equipotential surface between two points, but dimensionally surface between two points, but dimensionally it is not acceptable. Hence only option (c ) will be correct.
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