A short bar magnet experiences a torque of 0.012 Nm, with its axis placed at `60^@` with a uniform magnetic field of 0.4 T. What orientation of the magnet corresponds to its stable equilibrium in the magnetic field? Calculate the Potential energy in this position.

Explanation

To solve the problem step by step, we will follow the outlined process to find the orientation of the magnet corresponding to its stable equilibrium in the magnetic field and then calculate the potential energy in that position.

### Step 1: Identify the given data
- Torque (τ) = 0.012 Nm
- Angle (θ) = 60°
- Magnetic field (B) = 0.4 T

### Step 2: Use the formula for torque
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