A compass needle of magnetic moment `50 Am^2` experiences a torque of `1.3 xx 10^(-3)` Nm when pointing towards geographical north at a certain place where horizontal component of Earth's magnetic field is `30 mu Wb//m^2` . What is the declination of the place?

Explanation

To solve the problem of finding the declination of the place where a compass needle experiences a torque, we can follow these steps:

### Step 1: Identify the given values
We have the following values from the problem:
- Magnetic moment (M) = 50 Am²
- Torque (T) = 1.3 × 10^(-3) Nm
- Horizontal component of Earth's magnetic field (B) = 30 µWb/m² = 30 × 10^(-6) Wb/m² = 30 × 10^(-6) T

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