In an iron bar magnet of cross-section `2 cm^2` , `alpha` magnetic intensity of 1,200 A/m produces a magnetic flux of `3.2 xx 10^(-5) ` weber. Calculate the permeability and susceptibility of the iron bar.

Explanation

To solve the problem step by step, we will calculate the permeability and susceptibility of the iron bar magnet based on the given data.

### Given Data:
1. Cross-sectional area (A) = 2 cm² = \(2 \times 10^{-4} \, \text{m}^2\)
2. Magnetic intensity (H) = 1200 A/m
3. Magnetic flux (Φ) = \(3.2 \times 10^{-5} \, \text{Wb}\)

### Step 1: Calculate Magnetic Induction (B)
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