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For a specimen of iron weighing 15 kg th...

For a specimen of iron weighing 15 kg the hysteresis loss is equivalent to `400 Jm^(-3)` /cycle. Calculate the loss of energy per hour at 60 cycle/ s. Take density of iron = `7,500 kg//m^3`

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To solve the problem of calculating the loss of energy per hour due to hysteresis in a specimen of iron, we can follow these steps: ### Step-by-Step Solution 1. **Identify Given Data**: - Mass of iron specimen, \( m = 15 \, \text{kg} \) - Hysteresis loss, \( q = 400 \, \text{J/m}^3/\text{cycle} \) - Frequency of cycles, \( f = 60 \, \text{cycles/s} \) ...
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MODERN PUBLICATION-MAGNETISM AND MATTER-CHAPTER PRACTICE TEST FOR BOARD EXAMINATION
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  2. दो चुम्बकीय क्षेत्र रेखाएं परस्पर प्रतिच्छेद क्यों नहीं करती है ?

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