For a place, horizontal component of the earth's magnetic magnetic field is ` 3 xx 10^(-5) T` . Calculate the magnetic field of the earth at this place when angle of dip is `45^@` N.

Explanation

To solve the problem, we need to calculate the total magnetic field \( B \) of the Earth at a location where the horizontal component of the Earth's magnetic field \( B_h \) is given as \( 3 \times 10^{-5} \, \text{T} \) and the angle of dip \( \delta \) is \( 45^\circ \).

### Step-by-Step Solution:

1. **Understand the Relationship**: The horizontal component of the Earth's magnetic field \( B_h \) is related to the total magnetic field \( B \) and the angle of dip \( \delta \) by the equation:
\[ B_h = B \cos \delta \]
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