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Mean radius of a toroid carrying current...

Mean radius of a toroid carrying current of 2A is 30/`pi` cm. Total number of turns in toroid is 600. A paramagnetic substance is used to prepare a ring to make the core of toroid and its temperature is kept at 300 K. If intensity of magnetization in the core is `6.0 xx 10^(-2)` A/m. Find the magnetic susceptibility of the material at 300 K. How the intensity of magnetization will change when temperature of core is changed to 450 K?

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To solve the problem step by step, we will follow the given data and apply the relevant formulas. ### Given Data: - Mean radius of the toroid, \( R = \frac{30}{\pi} \) cm = \( \frac{30}{100} \) m = \( 0.3 \) m - Current, \( I = 2 \) A - Total number of turns, \( N = 600 \) - Intensity of magnetization, \( I = 6.0 \times 10^{-2} \) A/m - Temperature, \( T = 300 \) K ...
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