There is one short magnet of magnetic moment `2.16 Am^2` , which is placed on horizontal surface with its North Pole pointing towards north. Locate null point on horizontal surface if horizontal component of earth's magnetic field is `27 mu t` .

Explanation

To locate the null point on the horizontal surface due to the given short magnet and the Earth's magnetic field, we can follow these steps:

### Step 1: Understand the Problem
We have a short magnet with a magnetic moment \( M = 2.16 \, \text{A m}^2 \) placed on a horizontal surface with its North Pole pointing towards the north. The horizontal component of the Earth's magnetic field is given as \( B_H = 27 \, \mu T = 27 \times 10^{-6} \, T \).

### Step 2: Magnetic Field Due to the Short Magnet
The magnetic field \( B_m \) at a point along the axial line of a short magnet is given by the formula:
\[
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