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A bar magnet of magnetic moment M is pla...

A bar magnet of magnetic moment M is placed in a uniform magnetic field B in such a manner that is angle between M and B. Select the correct option(s)

A

Minimum potential energy is -MB

B

Maximum potential energy is MB

C

Bar magnet is in stable equilibrium when `theta = 0^@`

D

Bar magnet is in unstable equilibrium when ` theta = 180^@ `

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the behavior of a bar magnet in a uniform magnetic field, particularly focusing on the potential energy and the conditions for stable and unstable equilibrium. ### Step-by-Step Solution: 1. **Understanding the System**: - We have a bar magnet with a magnetic moment \( M \). - It is placed in a uniform magnetic field \( B \). - The angle between the magnetic moment \( M \) and the magnetic field \( B \) is denoted as \( \theta \). 2. **Potential Energy of the Magnet**: - The potential energy \( U \) of a magnetic moment \( M \) in a magnetic field \( B \) is given by the formula: \[ U = -\vec{M} \cdot \vec{B} = -MB \cos(\theta) \] - This means: - When \( \theta = 0^\circ \) (the magnet is aligned with the field), \( U = -MB \) (minimum potential energy). - When \( \theta = 90^\circ \) (the magnet is perpendicular to the field), \( U = 0 \) (potential energy is zero). - When \( \theta = 180^\circ \) (the magnet is anti-aligned with the field), \( U = +MB \) (maximum potential energy). 3. **Conditions for Equilibrium**: - **Stable Equilibrium**: Occurs when the potential energy is at a minimum. This happens at \( \theta = 0^\circ \). - **Unstable Equilibrium**: Occurs when the potential energy is at a maximum. This happens at \( \theta = 180^\circ \). 4. **Conclusion**: - The minimum potential energy is \( -MB \) when \( \theta = 0^\circ \). - The maximum potential energy is \( +MB \) when \( \theta = 180^\circ \). - Therefore, the bar magnet is in stable equilibrium when \( \theta = 0^\circ \) and in unstable equilibrium when \( \theta = 180^\circ \). ### Final Answers: - Minimum potential energy: \( -MB \) (correct) - Maximum potential energy: \( +MB \) (correct) - Stable equilibrium at \( \theta = 0^\circ \) (correct) - Unstable equilibrium at \( \theta = 180^\circ \) (correct)

To solve the problem, we need to analyze the behavior of a bar magnet in a uniform magnetic field, particularly focusing on the potential energy and the conditions for stable and unstable equilibrium. ### Step-by-Step Solution: 1. **Understanding the System**: - We have a bar magnet with a magnetic moment \( M \). - It is placed in a uniform magnetic field \( B \). - The angle between the magnetic moment \( M \) and the magnetic field \( B \) is denoted as \( \theta \). ...
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Knowledge Check

  • The torque acting on a magnet of magnetic moment 'M' placed in a uniform magnetic field B is

    A
    perpendicular to `vecM," parallel to "vec B`
    B
    parallel to `vecM," perpendicular to " vecB`
    C
    perpendicular to both `vecM and vec B`
    D
    parallel to both `vecM and vecB`.
  • A bar magnet of magnetic moment M is placed in a magnetic field of induction vec(B) . The torque exerted is

    A
    `vec(M) xx vec(B)`
    B
    `-vec(M) xx vec(B)`
    C
    `-vec(M).vec(B)`
    D
    `vec(M).vec(B)`
  • A bar magnet of magnetic moment barM is placed in a magnetic field of induction vecB, The torque exerted on it is

    A
    `vecM xx vecB`
    B
    `-vec M . vecB`
    C
    `vecM. vecB`
    D
    `vecB xx vecM`
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