Calculate the flux linked with a rectangular coil of area `10 cm xx 40 cm`, when it is placed in a magnetic field of 0.5 T with its plane
(i) normal to the field
(ii) parallel to the field
(iii) inclined at `30^(@)` with the field

Explanation

To solve the problem, we need to calculate the magnetic flux linked with a rectangular coil of area \(10 \, \text{cm} \times 40 \, \text{cm}\) in three different orientations with respect to a magnetic field of \(0.5 \, \text{T}\). The formula for magnetic flux (\(\Phi\)) is given by:

\[ \Phi = B \cdot A \cdot \cos(\theta) \]

where:
- \(B\) is the magnetic field strength,
...