A 100 turn coil of self-inductance 50 mH carries a current of 10 mA. Find the magnetic flux linked with each turn of coil.

Explanation

To find the magnetic flux linked with each turn of the coil, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Number of turns in the coil, \( N = 100 \)
- Self-inductance of the coil, \( L = 50 \, \text{mH} = 50 \times 10^{-3} \, \text{H} \)
- Current flowing through the coil, \( I = 10 \, \text{mA} = 10 \times 10^{-3} \, \text{A} \)
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